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What is the maximum number of electrons in an atom that can have the following quantum number?

What is the Maximum number of electrons in an atom that can have the following quantum number?
1) n=3 ms=+1/2
2) n=6 l=2
3)n=5 l=3 ml=+3
4) n=7 l=6 ml=+5
Help! Explain and answers please. Thank you.

read my answer here first…

http://answers.yahoo.com/question/index?qid=20100316122531AAUGm3B&r=w&show_comments=true&pa=FZB6NWHjDG3N56z6v_2wWE7yY8kQnOTffW8.R0KeXY4jsBu3r2qvng–&paid=add_comment#openions

then…
*** 1 ***
possible electrons…
(3,0,0,+1/2)
(3,1,-1,+1/2)
(3,1,0,+1/2)
(3,1,+1,+1/2)
(3,2,-2,+1/2)
(3,2,-1,+1/2)
(3,2,0,+1/2)
(3,2,+1,+1/2)
(3,2,+2,+1/2)
total = 9
or you might just notice that you have 1/2 of the s, p, and d electrons possible. 1/2 x (2+6+10) = 9

*** 2 ***
(6,2,-2, +1/2)
(6,2,-2, -1/2)
(6,2,-1, +1/2)
(6,2,-1, -1/2)
(6,2,0, +1/2)
(6,2,0, -1/2)
(6,2,+1, +1/2)
(6,2,+1, -1/2)
(6,2,+2, +1/2)
(6,2,+2, -1/2)
total = 10
or you might just notice that L=2 are the “d” electrons. there are 10 of them in each row.

*** 3 ***
(5,3,3,+1/2)
(5,3,3,-1/2)
total = 2

*** 4 ***
(7,6,+5, +1/2)
(7,6,+5, -1/2)
again.. 2 electrons.

******
questions?